Optimal. Leaf size=165 \[ -\frac{4 a^3}{d e^4 \sqrt{e \cot (c+d x)}}+\frac{4 a^3}{3 d e^3 (e \cot (c+d x))^{3/2}}+\frac{32 a^3}{35 d e^2 (e \cot (c+d x))^{5/2}}+\frac{2 \sqrt{2} a^3 \tanh ^{-1}\left (\frac{\sqrt{e} \cot (c+d x)+\sqrt{e}}{\sqrt{2} \sqrt{e \cot (c+d x)}}\right )}{d e^{9/2}}+\frac{2 \left (a^3 \cot (c+d x)+a^3\right )}{7 d e (e \cot (c+d x))^{7/2}} \]
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Rubi [A] time = 0.295887, antiderivative size = 165, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {3565, 3628, 3529, 3532, 208} \[ -\frac{4 a^3}{d e^4 \sqrt{e \cot (c+d x)}}+\frac{4 a^3}{3 d e^3 (e \cot (c+d x))^{3/2}}+\frac{32 a^3}{35 d e^2 (e \cot (c+d x))^{5/2}}+\frac{2 \sqrt{2} a^3 \tanh ^{-1}\left (\frac{\sqrt{e} \cot (c+d x)+\sqrt{e}}{\sqrt{2} \sqrt{e \cot (c+d x)}}\right )}{d e^{9/2}}+\frac{2 \left (a^3 \cot (c+d x)+a^3\right )}{7 d e (e \cot (c+d x))^{7/2}} \]
Antiderivative was successfully verified.
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Rule 3565
Rule 3628
Rule 3529
Rule 3532
Rule 208
Rubi steps
\begin{align*} \int \frac{(a+a \cot (c+d x))^3}{(e \cot (c+d x))^{9/2}} \, dx &=\frac{2 \left (a^3+a^3 \cot (c+d x)\right )}{7 d e (e \cot (c+d x))^{7/2}}-\frac{2 \int \frac{-8 a^3 e^2-7 a^3 e^2 \cot (c+d x)-a^3 e^2 \cot ^2(c+d x)}{(e \cot (c+d x))^{7/2}} \, dx}{7 e^3}\\ &=\frac{32 a^3}{35 d e^2 (e \cot (c+d x))^{5/2}}+\frac{2 \left (a^3+a^3 \cot (c+d x)\right )}{7 d e (e \cot (c+d x))^{7/2}}-\frac{2 \int \frac{-7 a^3 e^3+7 a^3 e^3 \cot (c+d x)}{(e \cot (c+d x))^{5/2}} \, dx}{7 e^5}\\ &=\frac{32 a^3}{35 d e^2 (e \cot (c+d x))^{5/2}}+\frac{4 a^3}{3 d e^3 (e \cot (c+d x))^{3/2}}+\frac{2 \left (a^3+a^3 \cot (c+d x)\right )}{7 d e (e \cot (c+d x))^{7/2}}-\frac{2 \int \frac{7 a^3 e^4+7 a^3 e^4 \cot (c+d x)}{(e \cot (c+d x))^{3/2}} \, dx}{7 e^7}\\ &=\frac{32 a^3}{35 d e^2 (e \cot (c+d x))^{5/2}}+\frac{4 a^3}{3 d e^3 (e \cot (c+d x))^{3/2}}-\frac{4 a^3}{d e^4 \sqrt{e \cot (c+d x)}}+\frac{2 \left (a^3+a^3 \cot (c+d x)\right )}{7 d e (e \cot (c+d x))^{7/2}}-\frac{2 \int \frac{7 a^3 e^5-7 a^3 e^5 \cot (c+d x)}{\sqrt{e \cot (c+d x)}} \, dx}{7 e^9}\\ &=\frac{32 a^3}{35 d e^2 (e \cot (c+d x))^{5/2}}+\frac{4 a^3}{3 d e^3 (e \cot (c+d x))^{3/2}}-\frac{4 a^3}{d e^4 \sqrt{e \cot (c+d x)}}+\frac{2 \left (a^3+a^3 \cot (c+d x)\right )}{7 d e (e \cot (c+d x))^{7/2}}+\frac{\left (28 a^6 e\right ) \operatorname{Subst}\left (\int \frac{1}{98 a^6 e^{10}-e x^2} \, dx,x,\frac{7 a^3 e^5+7 a^3 e^5 \cot (c+d x)}{\sqrt{e \cot (c+d x)}}\right )}{d}\\ &=\frac{2 \sqrt{2} a^3 \tanh ^{-1}\left (\frac{\sqrt{e}+\sqrt{e} \cot (c+d x)}{\sqrt{2} \sqrt{e \cot (c+d x)}}\right )}{d e^{9/2}}+\frac{32 a^3}{35 d e^2 (e \cot (c+d x))^{5/2}}+\frac{4 a^3}{3 d e^3 (e \cot (c+d x))^{3/2}}-\frac{4 a^3}{d e^4 \sqrt{e \cot (c+d x)}}+\frac{2 \left (a^3+a^3 \cot (c+d x)\right )}{7 d e (e \cot (c+d x))^{7/2}}\\ \end{align*}
Mathematica [C] time = 1.99668, size = 174, normalized size = 1.05 \[ \frac{2 a^3 \cos (c+d x) (\cot (c+d x)+1)^3 \left (35 \cos ^2(c+d x) \text{Hypergeometric2F1}\left (-\frac{3}{4},1,\frac{1}{4},-\cot ^2(c+d x)\right )+35 \cos ^2(c+d x) \cot (c+d x) \text{Hypergeometric2F1}\left (-\frac{1}{4},1,\frac{3}{4},-\cot ^2(c+d x)\right )+5 \sin ^2(c+d x) \text{Hypergeometric2F1}\left (-\frac{7}{4},1,-\frac{3}{4},-\cot ^2(c+d x)\right )+\frac{21}{2} \sin (2 (c+d x)) \text{Hypergeometric2F1}\left (-\frac{5}{4},1,-\frac{1}{4},-\cot ^2(c+d x)\right )\right )}{35 d (e \cot (c+d x))^{9/2} (\sin (c+d x)+\cos (c+d x))^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.026, size = 430, normalized size = 2.6 \begin{align*}{\frac{{a}^{3}\sqrt{2}}{2\,d{e}^{5}}\sqrt [4]{{e}^{2}}\ln \left ({ \left ( e\cot \left ( dx+c \right ) +\sqrt [4]{{e}^{2}}\sqrt{e\cot \left ( dx+c \right ) }\sqrt{2}+\sqrt{{e}^{2}} \right ) \left ( e\cot \left ( dx+c \right ) -\sqrt [4]{{e}^{2}}\sqrt{e\cot \left ( dx+c \right ) }\sqrt{2}+\sqrt{{e}^{2}} \right ) ^{-1}} \right ) }+{\frac{{a}^{3}\sqrt{2}}{d{e}^{5}}\sqrt [4]{{e}^{2}}\arctan \left ({\sqrt{2}\sqrt{e\cot \left ( dx+c \right ) }{\frac{1}{\sqrt [4]{{e}^{2}}}}}+1 \right ) }-{\frac{{a}^{3}\sqrt{2}}{d{e}^{5}}\sqrt [4]{{e}^{2}}\arctan \left ( -{\sqrt{2}\sqrt{e\cot \left ( dx+c \right ) }{\frac{1}{\sqrt [4]{{e}^{2}}}}}+1 \right ) }-{\frac{{a}^{3}\sqrt{2}}{2\,d{e}^{4}}\ln \left ({ \left ( e\cot \left ( dx+c \right ) -\sqrt [4]{{e}^{2}}\sqrt{e\cot \left ( dx+c \right ) }\sqrt{2}+\sqrt{{e}^{2}} \right ) \left ( e\cot \left ( dx+c \right ) +\sqrt [4]{{e}^{2}}\sqrt{e\cot \left ( dx+c \right ) }\sqrt{2}+\sqrt{{e}^{2}} \right ) ^{-1}} \right ){\frac{1}{\sqrt [4]{{e}^{2}}}}}-{\frac{{a}^{3}\sqrt{2}}{d{e}^{4}}\arctan \left ({\sqrt{2}\sqrt{e\cot \left ( dx+c \right ) }{\frac{1}{\sqrt [4]{{e}^{2}}}}}+1 \right ){\frac{1}{\sqrt [4]{{e}^{2}}}}}+{\frac{{a}^{3}\sqrt{2}}{d{e}^{4}}\arctan \left ( -{\sqrt{2}\sqrt{e\cot \left ( dx+c \right ) }{\frac{1}{\sqrt [4]{{e}^{2}}}}}+1 \right ){\frac{1}{\sqrt [4]{{e}^{2}}}}}+{\frac{2\,{a}^{3}}{7\,de} \left ( e\cot \left ( dx+c \right ) \right ) ^{-{\frac{7}{2}}}}+{\frac{6\,{a}^{3}}{5\,d{e}^{2}} \left ( e\cot \left ( dx+c \right ) \right ) ^{-{\frac{5}{2}}}}-4\,{\frac{{a}^{3}}{d{e}^{4}\sqrt{e\cot \left ( dx+c \right ) }}}+{\frac{4\,{a}^{3}}{3\,d{e}^{3}} \left ( e\cot \left ( dx+c \right ) \right ) ^{-{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.46721, size = 1262, normalized size = 7.65 \begin{align*} \left [\frac{\frac{105 \, \sqrt{2}{\left (a^{3} e \cos \left (2 \, d x + 2 \, c\right )^{2} + 2 \, a^{3} e \cos \left (2 \, d x + 2 \, c\right ) + a^{3} e\right )} \log \left (-\frac{\sqrt{2} \sqrt{\frac{e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}}{\left (\cos \left (2 \, d x + 2 \, c\right ) - \sin \left (2 \, d x + 2 \, c\right ) - 1\right )}}{\sqrt{e}} + 2 \, \sin \left (2 \, d x + 2 \, c\right ) + 1\right )}{\sqrt{e}} - 2 \,{\left (55 \, a^{3} \cos \left (2 \, d x + 2 \, c\right )^{2} + 30 \, a^{3} \cos \left (2 \, d x + 2 \, c\right ) - 85 \, a^{3} + 21 \,{\left (13 \, a^{3} \cos \left (2 \, d x + 2 \, c\right ) + 7 \, a^{3}\right )} \sin \left (2 \, d x + 2 \, c\right )\right )} \sqrt{\frac{e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}}}{105 \,{\left (d e^{5} \cos \left (2 \, d x + 2 \, c\right )^{2} + 2 \, d e^{5} \cos \left (2 \, d x + 2 \, c\right ) + d e^{5}\right )}}, -\frac{2 \,{\left (105 \, \sqrt{2}{\left (a^{3} e \cos \left (2 \, d x + 2 \, c\right )^{2} + 2 \, a^{3} e \cos \left (2 \, d x + 2 \, c\right ) + a^{3} e\right )} \sqrt{-\frac{1}{e}} \arctan \left (\frac{\sqrt{2} \sqrt{\frac{e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} \sqrt{-\frac{1}{e}}{\left (\cos \left (2 \, d x + 2 \, c\right ) + \sin \left (2 \, d x + 2 \, c\right ) + 1\right )}}{2 \,{\left (\cos \left (2 \, d x + 2 \, c\right ) + 1\right )}}\right ) +{\left (55 \, a^{3} \cos \left (2 \, d x + 2 \, c\right )^{2} + 30 \, a^{3} \cos \left (2 \, d x + 2 \, c\right ) - 85 \, a^{3} + 21 \,{\left (13 \, a^{3} \cos \left (2 \, d x + 2 \, c\right ) + 7 \, a^{3}\right )} \sin \left (2 \, d x + 2 \, c\right )\right )} \sqrt{\frac{e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}}\right )}}{105 \,{\left (d e^{5} \cos \left (2 \, d x + 2 \, c\right )^{2} + 2 \, d e^{5} \cos \left (2 \, d x + 2 \, c\right ) + d e^{5}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a \cot \left (d x + c\right ) + a\right )}^{3}}{\left (e \cot \left (d x + c\right )\right )^{\frac{9}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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